Example
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#1 dollymonroe ?
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- Posts: 4
- Joined: Yesterday, 06:33 PM
Posted Yesterday, 06:41 PM
I am having two issues with my program. 1) I cannot figure out how to loop to the next determination when the user enters more than one number. 2) How to print if a number is perfect or not perfect without it going into an infinite loop or printing it the same number of times as there are spots in the array.
public class csedersten_Perfect { /* * * * */ public static void main ( String args[] ) { int getN; int getP = getPerfect(); int [] perfect = new int[100]; int x = 1; boolean test = testPerfect(getP, perfect); while (x <= perfect.length) { printFactors(getP, perfect, test); } } /* * * * */ public static int getNum() { Scanner i = new Scanner( System.in ); int num; // int perfectNum = 1; // int total = 0; // System.out.print( "How many numbers would you like to test? "); num = i.nextInt(); boolean validateN = validateNum(num, perfectNum); while (!validateN) { System.out.print( "How many numbers would you like to test? "); num = i.nextInt(); validateN = validateNum(num, perfectNum); } return num; } /* * * * */ public static boolean validateNum( int num, int perfectNum ) { if (( num <= 0 ) || ( perfectNum <= 0 )) { System.out.println( " Non-positive numbers are not allowed." ); } else { return true; } return false; } /* * * * */ public static int getPerfect() { Scanner i = new Scanner ( System.in ); int perfectNum = -1; int num = getNum(); System.out.print( "Please enter a possible perfect number: " ); perfectNum = i.nextInt(); boolean validateN = validateNum(perfectNum, num); while (!validateN) { System.out.print( "Please enter a possible perfect number: " ); perfectNum = i.nextInt(); validateN = validateNum(perfectNum, num); } return perfectNum; } /* * * * */ public static boolean testPerfect( int perfectNum, int[] perfect ) { int max = perfectNum; int a = 0; int sum = 0; for (int x = 1; x <= max; x++) { perfect[a++] = x; perfectNum /= x; } perfect[a] = perfectNum; for (int x = 0; x < perfect.length; x++) { sum += perfect[x]; } if (sum == perfectNum) { int[] p = perfect; return true; } else { return false; } } /* * * * */ public static void printFactors( int perfectNum, int[] perfect, boolean test) { if (test == true) { System.out.printf( "%d:%10d", perfectNum, perfect); } else { System.out.printf( "%d:NOT PERFECT", perfectNum ); } } }
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Replies To: Determine perfect number, error with infinite loop
#2 Flukeshot ?
Reputation: 114
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- Joined: 14-November 12
Re: Determine perfect number, error with infinite loop
Posted Yesterday, 06:49 PM
Your while loop is riding on the integer x being less than 100, it is set to 1. There is nothing in your code that will make x ever be more than 100, hence, you have an infinite loop.
#3 dollymonroe ?
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- Posts: 4
- Joined: Yesterday, 06:33 PM
Re: Determine perfect number, error with infinite loop
Posted Yesterday, 07:06 PM
I understand what you're saying, but when I enter a number to determine if it is perfect or not perfect, the program doesn't stop printing the same thing over and over. I have to type ctrl c to escape it. I was wondering how to fix that.
#4 Flukeshot ?
Reputation: 114
- Posts: 353
- Joined: 14-November 12
Re: Determine perfect number, error with infinite loop
Posted Yesterday, 07:19 PM
You obviously didn't understand what I said, because addressing the issue I pointed out would correct your infinite loop that's printing everything out.while (x <= perfect.length)
The int 'x' is 1.
The length of your array 'perfect' is [100]
You never change x in your code. x is always <= perfect.length.
I think you are trying to track how many inputs there are, an array length is not the way to do this since arrays have a set length at birth. What you will want to do is have a variable to record the number of inputs, and use that value in a for loop.
//class variable static int numberOfInputs = 0; //in your getPerfect() method System.out.print( "Please enter a possible perfect number: " ); perfectNum = i.nextInt(); numberOfInputs++; //your for loop for(int i = 0; i < numberOfInputs; i++) { print }
#5 pbl ?
Reputation: 7855
- Posts: 30,702
- Joined: 06-March 08
Re: Determine perfect number, error with infinite loop
Posted Yesterday, 07:28 PM
This does not really make sense
int max = perfectNum; int a = 0; int sum = 0; for (int x = 1; x <= max; x++) { perfect[a++] = x; perfectNum /= x; }
so you store
perfect[0] = 1
perfect[1] = 2
perfect[2] = 3
.... up to
perfect[max]
at the same time assuming perfectNum == 10 which mean max == 10
you will
perfectNum /= 1
perfectNum /= 2
...
perfectNum /= 10
sure that perfectNum will be == 0 at the end of the loop
#6 dollymonroe ?
Reputation: 0
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- Joined: Yesterday, 06:33 PM
Re: Determine perfect number, error with infinite loop
Posted Yesterday, 07:40 PM
Flukeshot, I would use that solution if I could, but I am not allowed to use global variables for this assignment.
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